Farthest by Manhattan — Solution & Editorial

Back to the Problem

Chebyshev transform: with u = x+y and v = x−y, Manhattan distance equals max(|Δu|, |Δv|), so the answer is max(range of u, range of v) — no pair enumeration.

Complexity: O(N)

Watch out: O(N²) pair checking times out; the u/v rotation is the entire trick.