The Final Exam — Solution & Editorial
Need total ≥ N·T, so answer = max(0, N·T − current sum), checked against 100 — all in integers.
Complexity: O(1) or O(log)
Need total ≥ N·T, so answer = max(0, N·T − current sum), checked against 100 — all in integers.
Complexity: O(1) or O(log)