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Problems > Two Remainder Conditions > Editorial

Two Remainder Conditions — Solution & Editorial

Back to the Problem

Chinese Remainder: x = A + M·k where k ≡ (B−A)·M−1 (mod N); the inverse exists by coprimality. If the result is 0, the smallest positive is MN.

Complexity: O(log)

Watch out: A = B = 0 makes x = 0 — the smallest POSITIVE answer is then M·N.