Counting Routes in a DAG — Solution & Editorial
Topologically sort, then DP: ways[v] = ∑ ways[u] over predecessors, seeded with ways[1] = 1.
Complexity: O(N + M)
Topologically sort, then DP: ways[v] = ∑ ways[u] over predecessors, seeded with ways[1] = 1.
Complexity: O(N + M)